wait, is 3 to the power of 3... 3 x 3 x 3? Like 3 x 3 sets of x 3? Okay, I get it. (I think)/half sure. I can sleep tonight.
I thought squared was also 'to the power of' but you're right. there's no ^ meaning it's not to the power of. 3 squared is 9, lol, my shock when I thought 3 squared was 27, almost lost sleep over it j/k, but yeah, now I'm with you. 3 squared is 9 and 3 to the power of 3 isn't the same as 3 squared.
7 + 7 / 7 + 7x7 - 7 is 50 because........................... 7 x 7 = 49 7 / 7 = 1 49 + 1 = 50. 7 + 50 = 57 & 57 - 7 = 50
I'll stand with my 39 hours of college work in algebra and calculus and 10 years programming in COBOL, FORTRAN, BASIC, and C. Parentheses Exponents Multiplication Division Addition Subtraction or PEMDAS PEMDAS been working since the 1,500s. Not changing because of some internet video.
Yeah I had plenty of math and programmed in FORTRAN, COBOL, Visual Basic, etc too, and it doesn't matter mathematically whether it is written 6÷2(1+2) or 6/2*(1+2) or (6/2)*(1+2), multiplication is being done on (1+2) so that has to be resolved first. Then it's left-to-right as 6/2*3. To make it 1 it would have to be written 6/(2(1+2)).
The rule is Multiplication and division are equals (as they are the same operation), and then you go left to right. PEMDAS is a new invention and it's wrong--I never learned about it when I was in calculus in the 1980s. https://www.wyzant.com/resources/bl...hat_you_learned_in_elementary_school_is_wrong Really, PE(MD)(AS) is a more accurate way to explain it, or in other words PEMDAS is ambigious, and PEDMAS or PEMDSA or PEDMSA is also correct. Order of operations hasn't changed. You are simply mis-applying them. That said, the first time I did the problem, I got the answer 1, but on re-examination, the answer is 9. The problem was designed to be a trick problem based on the technicality that multiplication and division are on the same level, and you work same level problems left to right. I fell for the trick (the first time) as well. In the real world, nobody would have written such a silly equation. They would have made it more clear, and there would be no doubt what the problem really was.
PEMDAS order of operation Parentheses then Exponents then Multiplication then Division then Addition then Subtraction and left to right within each group. Method accepted since 1500s. so it is 1+2 = 3 2*3 =6 6/6 = 1
I was doing PEMDAS in 1963. The method dates back to the 1500s. This book https://www.amazon.com/American-mental-arithmetic-M-Bailey/dp/1176179780 From 1923 describes it . Follow the rules and you always get the same answer.
That violates the rules of math. The "M" in "PEMDAS" is to be done left to right. Tell you what. Find a reliable mathematician (a local school should have one) and ask him/her, then get back to me. Meanwhile, you can save steps by checking these: http://mathforum.org/dr.math/faq/faq.order.operations.html https://duckduckgo.com/?q=6/2(1+2)&t=h_&search_plus_one=form&ia=calculator
Ok, ok. Let me show you your error. Problem: 6÷2(1+2) Resolve anything in parenthesis: 6÷2(3) or 6/2(3) or 6/2*3 (all the same). No exponents? Then carry out multiplication and division (equal priority for both) left to right: Here you went right to left. You resolved 2(3) first before dealing with the 6. VIOLATION!!!! Go RIGHT to LEFT: 6/2(3) Resolve 6/2 first... =3 So 3(3) = 9
Well, I'm certainly no mathematician, but I'm pretty sure that you solve the problem in the parentheses first, and the parentheses mean to multiply that number. So it would be 1 plus 2 equals 3 and then 6 divided by 2 is 3. Then you multiply the numbers which would give you 9. Algebra!
M is done before D...A is done before S... Since the 16th century. Follow the rules and there are no ambiguities.
Parentheses Exponents Multiplication and Division left to right Addition and Subtraction left to right We could always askamathematician... http://www.askamathematician.com/20...-deal-with-this-orders-of-operation-business/
You're wrong. Multiplication and division are of equal significance and so are done left-to-right. https://www.mathsisfun.com/operation-order-pemdas.html https://www.purplemath.com/modules/orderops.htm Here, example 3 [5/5*2] has division in step 2 before multiplication in step 3. http://www.mathgoodies.com/Lessons/vol7/order_operations.html Here's another: "Step 3) Multiplication and Division. Go from left to right performing all the multiplication and division as you come across it, so divide 6 by 2 to get 3, and multiply that by 11 to get 33." Division first because it is on the left of the multiplication. https://www.freemathhelp.com/order-of-operations.html This will do it for you: http://calculator.swiftutors.com/order-of-operations-calculator.html How many would you like? I provided 5 sources of proof. What can you provide?
Instead of division, just raise it to the power of -1 and use multiplication. Then you don't need division.
Okay, I get it now! 6÷2(1+2) 6÷(2×1)+(2×2) 6÷(2+4) 6÷6 =1 For someone who has always hated math, who has not done any kind of math since 2010 and who passed high school maths nearly dying on the way, this was quite difficult lol. But, I totally get it now. I was just a bit rusty in this matter.
Division is really just multiplication. Why not reduce it all to bit addition and shifts. Let's get fundamental! [Didn't Olivia Newton John do that song?]
Math is just a bunch of definitions. It does not really exist anyway. It's all in your head. Same as time. Time does not exist either.
Okay, watched the video and apparently my way of doing it is "outdated". I am not surprised though, my high school math teacher was about 100 years old so not surprised she taught us the "historical method".
Alright Mr. Descartes. However, as it turns out, information may in fact be all that really does exist. And Math is information - a set of highly structured rules. It has been shown that information and energy are related such that useful [structured] information can do work. If something can do work it must exist. Therefore math does exist. In fact, math is the most highly structured information set in existence. It is the purest form of logic.