Quote:
Originally Posted by Rotaerk
If in your model of the world a(x)->b(x), then yes, logically, ~b(x)->~a(x), but that is irrelevant. You and Herkdriver both seemed to be attempting to prove a(x)->b(x) by using the identity a(x)->b(x)<=>~b(x)->~a(x), without first showing that ~b(x)->~a(x). Stop losing sight of the point of the discussion. "He showed that my deduction was illogical, so I'll go off on a completely different tangent to be right about something else."
|
HELLO?! I'm providing my model as a proof for the second side,
Quote:
|
if a process is unintelligent, it only produces unintelligent beings.
|
if this model is wrong, my whole statement becomes rejected, but not till then.